What is laplac(e^{2t}-36)u(t-7) ?

The solution to laplac(e^{2t}-36)u(t-7) is l^2a^2pcu(t-7)(e^{2t}-36)

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simplify laplac(e^{2t}-36)u(t-7)

simplify

l a pl a c (e^{2 t} - 36) u (t - 7)

l^{2} a^{2} p c u (t - 7) (e^{2 t} - 36)

Solution steps

l a pl a c (e^{2 t} - 36) u (t - 7)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

ll = l^{1 + 1}

= a p l^{1 + 1} a c (e^{2 t} - 36) u (t - 7)

Add the numbers:

1 + 1 = 2

= a p l^{2} a c (e^{2 t} - 36) u (t - 7)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

aa = a^{1 + 1}

= p l^{2} a^{1 + 1} c (e^{2 t} - 36) u (t - 7)

Add the numbers:

1 + 1 = 2

= p l^{2} a^{2} c (e^{2 t} - 36) u (t - 7)

4^{\frac{1}{3}} 2^{\frac{1}{3}}

((\frac{2}{3})^{'})^{- 2}

155 e^{- \frac{p}{50}}

e^{- 3 s} L {\frac{e ^{(t + 3) - 2}}{5}}

e^{- λ}

What is laplac(e^{2t}-36)u(t-7) ?
The solution to laplac(e^{2t}-36)u(t-7) is l^2a^2pcu(t-7)(e^{2t}-36)