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Popular >

simplify f^{-1}(2+2x+e^{2x})

Solution

simplify

f^{- 1} (2 + 2 x + e^{2 x})

Solution

\frac{2 x + e ^{2 x} + 2}{f}

Solution steps

f^{- 1} (2 + 2 x + e^{2 x})

Apply exponent rule:

a^{- 1} = \frac{1}{a}

= \frac{1}{f} (2 x + e^{2 x} + 2)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ( 2 + 2 x + e ^{2 x} )}{f}

1 \cdot (2 + 2 x + e^{2 x}) = 2 + 2 x + e^{2 x}

= \frac{2 + 2 x + e ^{2 x}}{f}

Popular Examples

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1.83 \cdot 1 0^{- 6} \cdot 0.000617 \cdot 76.395

simplify (sqrt(100e^{20x)+e^{-2x}})^3 simplify

(100 e^{20 x} + e^{- 2 x})^{3}

simplify 10e^{-1/((108*0.002))}simplify

10 e^{- \frac{1}{( 108 \cdot 0.002 )}}

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simplify (2.25*10^{-2})((0.28)^2)simplify

(2.25 \cdot 1 0^{- 2}) ((0.28)^{2})

Frequently Asked Questions (FAQ)

What is f^{-1}(2+2x+e^{2x}) ?
The solution to f^{-1}(2+2x+e^{2x}) is (2x+e^{2x}+2)/f