What is (x^2+3x-5)^2(x^2+1)^2 ?

The solution to (x^2+3x-5)^2(x^2+1)^2 is (x^2+1)^2(x^2+3x-5)^2

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simplify (x^2+3x-5)^2(x^2+1)^2

simplify

(x^{2} + 3 x - 5)^{2} (x^{2} + 1)^{2}

(x^{2} + 1)^{2} (x^{2} + 3 x - 5)^{2}

Solution steps

(x^{2} + 3 x - 5)^{2} (x^{2} + 1)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x^{2} + 3 x - 5)^{2} (x^{2} + 1)^{2} = ((x^{2} + 3 x - 5) (x^{2} + 1))^{2}

= ((x^{2} + 3 x - 5) (x^{2} + 1))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (x^{2} + 3 x - 5)^{2} (x^{2} + 1)^{2}

(2 t^{2}) (2 t)

9 x^{2} (C n (n + r) x^{n + r - 1})

e^{- (- 3)}

- 15.6 \cdot 1 0^{- 5}

What is (x^2+3x-5)^2(x^2+1)^2 ?
The solution to (x^2+3x-5)^2(x^2+1)^2 is (x^2+1)^2(x^2+3x-5)^2