What is e^{-ln((1+x)/(1-x))} ?

The solution to e^{-ln((1+x)/(1-x))} is (-x+1)/(x+1)

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simplify e^{-ln((1+x)/(1-x))}

simplify

e^{- l n (\frac{1 + x}{1 - x})}

\frac{- x + 1}{x + 1}

Solution steps

e^{- l n (\frac{1 + x}{1 - x})}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{l n (\frac{1 + x}{1 - x})}}

e^{l n (\frac{1 + x}{1 - x})} = \frac{1 + x}{1 - x}

= \frac{1}{\frac{1 + x}{1 - x}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{1 - x}{1 + x}

e^{- 3 x} e^{- x}

10^{\frac{1}{3}}

What is e^{-ln((1+x)/(1-x))} ?
The solution to e^{-ln((1+x)/(1-x))} is (-x+1)/(x+1)