What is sqrt(x^2-9)sqrt(16-x^2) ?

The solution to sqrt(x^2-9)sqrt(16-x^2) is sqrt((x^2-9)(-x^2+16))

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simplify sqrt(x^2-9)sqrt(16-x^2)

simplify

x^{2} - 9 16 - x^{2}

(x^{2} - 9) (- x^{2} + 16)

Solution steps

x^{2} - 9 16 - x^{2}

Apply radical rule:

a b = a \cdot b,

assuming

a \geq 0, b \geq 0

x^{2} - 9 - x^{2} + 16 = (x^{2} - 9) (- x^{2} + 16)

= (x^{2} - 9) (- x^{2} + 16)

1 - cos (x) \times 1 + cos (x)

4 (3)^{2}

4 (3)^{3}

\frac{e ^{x}}{e ^{x - 1}}

(4 x^{2}) (6 x^{6})

What is sqrt(x^2-9)sqrt(16-x^2) ?
The solution to sqrt(x^2-9)sqrt(16-x^2) is sqrt((x^2-9)(-x^2+16))