What is (x+3)(x+1)^2(x-1)^2 ?

The solution to (x+3)(x+1)^2(x-1)^2 is (x+1)^2(x-1)^2(x+3)

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simplify (x+3)(x+1)^2(x-1)^2

simplify

(x + 3) (x + 1)^{2} (x - 1)^{2}

(x + 1)^{2} (x - 1)^{2} (x + 3)

Solution steps

(x + 3) (x + 1)^{2} (x - 1)^{2}

Apply exponent rule:

a^{m} b^{m} = (ab)^{m},

assuming

a \geq 0, b \geq 0

(x + 1)^{2} (x - 1)^{2} = ((x + 1) (x - 1))^{2}

= (x + 3) ((x + 1) (x - 1))^{2}

((x + 1) (x - 1))^{2} = (x + 1)^{2} (x - 1)^{2}

= (x + 3) (x + 1)^{2} (x - 1)^{2}

3 t \cdot (e^{2 t})^{2} \cdot 2 e^{2 t}

(a + b) (a - b)

(\frac{π}{3})^{- 1}

(25) (45)

e^{- l n (∣ x - n^{2} v ∣^{\frac{1}{q}})}

What is (x+3)(x+1)^2(x-1)^2 ?
The solution to (x+3)(x+1)^2(x-1)^2 is (x+1)^2(x-1)^2(x+3)