What is (9x^{2a-4}b^{4a+6})(8x^{3a+2}b^{5a+5}) ?

The solution to (9x^{2a-4}b^{4a+6})(8x^{3a+2}b^{5a+5}) is 72b^{9a+11}x^{5a-2}

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simplify (9x^{2a-4}b^{4a+6})(8x^{3a+2}b^{5a+5})

simplify

(9 x^{2 a - 4} b^{4 a + 6}) (8 x^{3 a + 2} b^{5 a + 5})

72 b^{9 a + 11} x^{5 a - 2}

Solution steps

(9 x^{2 a - 4} b^{4 a + 6}) (8 x^{3 a + 2} b^{5 a + 5})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

b^{4 a + 6} b^{5 a + 5} = b^{4 a + 6 + 5 a + 5}

= 9 x^{2 a - 4} \cdot 8 x^{3 a + 2} b^{4 a + 6 + 5 a + 5}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{2 a - 4} x^{3 a + 2} = x^{2 a - 4 + 3 a + 2}

= 9 \cdot 8 x^{2 a - 4 + 3 a + 2} b^{4 a + 6 + 5 a + 5}

Simplify

2 a - 4 + 3 a + 2 : 5 a - 2

= 9 \cdot 8 b^{4 a + 5 a + 6 + 5} x^{5 a - 2}

b^{4 a + 6 + 5 a + 5} = b^{9 a + 11}

= 9 \cdot 8 b^{9 a + 11} x^{5 a - 2}

Multiply the numbers:

9 \cdot 8 = 72

= 72 b^{9 a + 11} x^{5 a - 2}

((5)^{2} + (53)^{2})^{2}

e^{- x} (- x + 1) (\frac{1}{2} x^{2} - 2 x + 1)

(5 + 3) (5 + 3)

f (x) = (e^{- \frac{x}{4}})^{2}

What is (9x^{2a-4}b^{4a+6})(8x^{3a+2}b^{5a+5}) ?
The solution to (9x^{2a-4}b^{4a+6})(8x^{3a+2}b^{5a+5}) is 72b^{9a+11}x^{5a-2}