What is (e^t+e^{-t})(e^t+e^{-t}) ?

The solution to (e^t+e^{-t})(e^t+e^{-t}) is (e^t+e^{-t})^2

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simplify (e^t+e^{-t})(e^t+e^{-t})

simplify

(e^{t} + e^{- t}) (e^{t} + e^{- t})

(e^{t} + e^{- t})^{2}

Solution steps

(e^{t} + e^{- t}) (e^{t} + e^{- t})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

(e^{t} + e^{- t}) (e^{t} + e^{- t}) = (e^{t} + e^{- t})^{1 + 1}

= (e^{t} + e^{- t})^{1 + 1}

Add the numbers:

1 + 1 = 2

= (e^{t} + e^{- t})^{2}

5.2 \times 1 0^{- 3}

5.2 \times 1 0^{- 2}

1 0^{- 15}

What is (e^t+e^{-t})(e^t+e^{-t}) ?
The solution to (e^t+e^{-t})(e^t+e^{-t}) is (e^t+e^{-t})^2