What is log_{6}(10)+log_{6}(15) ?

The solution to log_{6}(10)+log_{6}(15) is log_{6}(150)

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simplify log_{6}(10)+log_{6}(15)

simplify

lo g_{6} (10) + lo g_{6} (15)

lo g_{6} (150)

Solution steps

lo g_{6} (10) + lo g_{6} (15)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{6} (10) + lo g_{6} (15) = lo g_{6} (10 \cdot 15)

= lo g_{6} (10 \cdot 15)

Multiply the numbers:

10 \cdot 15 = 150

= lo g_{6} (150)

ln (\frac{6}{e ^{2}})

2 lo g_{10} (x) + 3 lo g_{10} (x + 1)

ln (\frac{1 0 ^{- 4} x ^{- 2}}{x ^{5}})

- \frac{2}{5} lo g_{2} (\frac{2}{5}) - \frac{3}{5} lo g_{2} (\frac{3}{5})

lo g_{10} (\frac{x}{10})

What is log_{6}(10)+log_{6}(15) ?
The solution to log_{6}(10)+log_{6}(15) is log_{6}(150)