What is log_{10}(2ab) ?

The solution to log_{10}(2ab) is log_{10}(2)+log_{10}(a)+log_{10}(b)

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simplify log_{10}(2ab)

simplify

lo g_{10} (2 ab)

lo g_{10} (2) + lo g_{10} (a) + lo g_{10} (b)

Solution steps

lo g_{10} (2 ab)

Apply log rule:

lo g_{a} (x y) = lo g_{a} (x) + lo g_{a} (y)

lo g_{10} (2 ab) = lo g_{10} (2) + lo g_{10} (a) + lo g_{10} (b)

= lo g_{10} (2) + lo g_{10} (a) + lo g_{10} (b)

lo g_{10} (a b^{2})

lo g_{3} (\frac{81}{x ^{2} + 5})

- lo g_{10} (\frac{1}{x})

lo g_{5} (125 x)

What is log_{10}(2ab) ?
The solution to log_{10}(2ab) is log_{10}(2)+log_{10}(a)+log_{10}(b)