What is expand log_{10}((2x)/5) ?

The solution to expand log_{10}((2x)/5) is log_{10}(2)+log_{10}(x)-log_{10}(5)

Popular >

expand log_{10}((2x)/5)

expand

lo g_{10} (\frac{2 x}{5})

lo g_{10} (2) + lo g_{10} (x) - lo g_{10} (5)

Solution steps

lo g_{10} (\frac{2 x}{5})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{2 x}{5}) = lo g_{10} (2 x) - lo g_{10} (5)

= lo g_{10} (2 x) - lo g_{10} (5)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (2 x) = lo g_{10} (2) + lo g_{10} (x)

= lo g_{10} (2) + lo g_{10} (x) - lo g_{10} (5)

lo g_{10} (x) + lo g_{10} (y) - lo g_{10} (z)

lo g_{10} ((a + b)^{2}) - lo g_{10} (a + b)

ln (2 π)

ln (2 x) - ln (x)

lo g_{10} (x) - 2 lo g_{10} (y) + 5 lo g_{10} (z)

What is expand log_{10}((2x)/5) ?
The solution to expand log_{10}((2x)/5) is log_{10}(2)+log_{10}(x)-log_{10}(5)