What is log_{10}(3)+log_{10}(2) ?

The solution to log_{10}(3)+log_{10}(2) is log_{10}(6)

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simplify log_{10}(3)+log_{10}(2)

simplify

lo g_{10} (3) + lo g_{10} (2)

lo g_{10} (6)

Solution steps

lo g_{10} (3) + lo g_{10} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (3) + lo g_{10} (2) = lo g_{10} (3 \cdot 2)

= lo g_{10} (3 \cdot 2)

Multiply the numbers:

3 \cdot 2 = 6

= lo g_{10} (6)

lo g_{10} (12) + \frac{1}{2} lo g_{10} (7) - lo g_{10} (2)

lo g_{10} (3) + lo g_{10} (4)

lo g_{10} (\frac{6 ( x + 4 ) ^{3}}{x ^{5}})

ln (5 e^{6})

- \frac{1}{4} lo g_{2} (\frac{1}{4}) - \frac{3}{4} lo g_{2} (\frac{3}{4})

What is log_{10}(3)+log_{10}(2) ?
The solution to log_{10}(3)+log_{10}(2) is log_{10}(6)