What is log_{10}(4)+log_{10}(6)-log_{10}(2) ?

The solution to log_{10}(4)+log_{10}(6)-log_{10}(2) is log_{10}(12)

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simplify log_{10}(4)+log_{10}(6)-log_{10}(2)

simplify

lo g_{10} (4) + lo g_{10} (6) - lo g_{10} (2)

lo g_{10} (12)

Decimal Notation

1.07918 \dots

Solution steps

lo g_{10} (4) + lo g_{10} (6) - lo g_{10} (2)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (4) + lo g_{10} (6) = lo g_{10} (4 \cdot 6)

= lo g_{10} (4 \cdot 6) - lo g_{10} (2)

Multiply the numbers:

4 \cdot 6 = 24

= lo g_{10} (24) - lo g_{10} (2)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (24) - lo g_{10} (2) = lo g_{10} (\frac{24}{2})

= lo g_{10} (\frac{24}{2})

Divide the numbers:

\frac{24}{2} = 12

= lo g_{10} (12)

lo g_{15} (15 x)

lo g_{10} (15) + lo g_{10} (2) - lo g_{10} (5)

lo g_{7} (49 x)

lo g_{4} (2) + 2 lo g_{4} (7)

lo g_{2} (16 x)

What is log_{10}(4)+log_{10}(6)-log_{10}(2) ?
The solution to log_{10}(4)+log_{10}(6)-log_{10}(2) is log_{10}(12)