What is log_{2}(27/3)-log_{2}(16/2) ?

The solution to log_{2}(27/3)-log_{2}(16/2) is log_{2}(9/8)

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simplify log_{2}(27/3)-log_{2}(16/2)

simplify

lo g_{2} (\frac{27}{3}) - lo g_{2} (\frac{16}{2})

lo g_{2} (\frac{9}{8})

Decimal Notation

0.16992 \dots

Solution steps

lo g_{2} (\frac{27}{3}) - lo g_{2} (\frac{16}{2})

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{2} (\frac{27}{3}) - lo g_{2} (\frac{16}{2}) = lo g_{2} (\frac{\frac{27}{3}}{\frac{16}{2}})

= lo g_{2} (\frac{\frac{27}{3}}{\frac{16}{2}})

\frac{\frac{27}{3}}{\frac{16}{2}} = \frac{9}{8}

= lo g_{2} (\frac{9}{8})

lo g_{5} (\frac{x}{25})

lo g_{3} (5 x)

lo g_{10} (\frac{10}{y})

ln (\frac{e}{2})

lo g_{10} (a) - lo g_{10} (b)

What is log_{2}(27/3)-log_{2}(16/2) ?
The solution to log_{2}(27/3)-log_{2}(16/2) is log_{2}(9/8)