What is expand log_{5}(2x(8x+7)) ?

The solution to expand log_{5}(2x(8x+7)) is log_{5}(2)+log_{5}(x)+log_{5}(8x+7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand log_{5}(2x(8x+7))

expand

lo g_{5} (2 x (8 x + 7))

lo g_{5} (2) + lo g_{5} (x) + lo g_{5} (8 x + 7)

Solution steps

lo g_{5} (2 x (8 x + 7))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{5} (2 x (8 x + 7)) = lo g_{5} (2) + lo g_{5} (x) + lo g_{5} (8 x + 7)

= lo g_{5} (2) + lo g_{5} (x) + lo g_{5} (8 x + 7)

ln (ln (4)) - ln (ln (2))

lo g_{10} (y) + 11 lo g_{10} (z)

lo g_{10} (\frac{100 x ^{2}}{27})

lo g_{10} (\frac{z}{3} (t - 2))

What is expand log_{5}(2x(8x+7)) ?
The solution to expand log_{5}(2x(8x+7)) is log_{5}(2)+log_{5}(x)+log_{5}(8x+7)