What is expand log_{5}(w/(2b)) ?

The solution to expand log_{5}(w/(2b)) is log_{5}(w)-log_{5}(2)-log_{5}(b)

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expand log_{5}(w/(2b))

expand

lo g_{5} (\frac{w}{2 b})

lo g_{5} (w) - lo g_{5} (2) - lo g_{5} (b)

Solution steps

lo g_{5} (\frac{w}{2 b})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{5} (\frac{w}{2 b}) = lo g_{5} (w) - lo g_{5} (2 b)

= lo g_{5} (w) - lo g_{5} (2 b)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{5} (2 b) = lo g_{5} (2) + lo g_{5} (b)

= lo g_{5} (w) - (lo g_{5} (b) + lo g_{5} (2))

- (lo g_{5} (2) + lo g_{5} (b)) : - lo g_{5} (2) - lo g_{5} (b)

= lo g_{5} (w) - lo g_{5} (2) - lo g_{5} (b)

lo g_{10} (\frac{3 x}{11})

ln (\frac{e ^{2}}{5})

lo g_{10} (\frac{y}{100})

\frac{1}{4} lo g_{6} (w) + 2 lo g_{6} (y) - lo g_{6} (x)

lo g_{6} (\frac{36}{x + 1})

What is expand log_{5}(w/(2b)) ?
The solution to expand log_{5}(w/(2b)) is log_{5}(w)-log_{5}(2)-log_{5}(b)