What is log_{10}(a+b)+log_{10}(a-b) ?

The solution to log_{10}(a+b)+log_{10}(a-b) is log_{10}((a+b)(a-b))

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simplify log_{10}(a+b)+log_{10}(a-b)

simplify

lo g_{10} (a + b) + lo g_{10} (a - b)

lo g_{10} ((a + b) (a - b))

Solution steps

lo g_{10} (a + b) + lo g_{10} (a - b)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (a + b) + lo g_{10} (a - b) = lo g_{10} ((a + b) (a - b))

= lo g_{10} ((a + b) (a - b))

4 lo g_{b} (x + 2) - \frac{1}{3} lo g_{b} (x - 5)

ln (\frac{4 m ^{5}}{p})

ln (\frac{x ^{3}}{y ^{2}})

lo g_{5} (x^{2}) - 3 lo g_{5} (x)

2 lo g_{10} (3) + 3 lo g_{10} (2)

What is log_{10}(a+b)+log_{10}(a-b) ?
The solution to log_{10}(a+b)+log_{10}(a-b) is log_{10}((a+b)(a-b))