What is log_{10}(2x^4)+log_{10}(3x^5) ?

The solution to log_{10}(2x^4)+log_{10}(3x^5) is log_{10}(6x^9)

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simplify log_{10}(2x^4)+log_{10}(3x^5)

simplify

lo g_{10} (2 x^{4}) + lo g_{10} (3 x^{5})

lo g_{10} (6 x^{9})

Solution steps

lo g_{10} (2 x^{4}) + lo g_{10} (3 x^{5})

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (2 x^{4}) + lo g_{10} (3 x^{5}) = lo g_{10} (2 x^{4} \cdot 3 x^{5})

= lo g_{10} (2 x^{4} \cdot 3 x^{5})

Simplify

2 x^{4} \cdot 3 x^{5} : 6 x^{9}

= lo g_{10} (6 x^{9})

ln (y) + ln (z)

lo g_{10} (\frac{y}{4 y + 8})

ln ((sin (x))^{x})

lo g_{10} (\frac{x ^{3} y ^{2}}{z})

What is log_{10}(2x^4)+log_{10}(3x^5) ?
The solution to log_{10}(2x^4)+log_{10}(3x^5) is log_{10}(6x^9)