What is log_{10}(2)+log_{10}(3)+log_{10}(4) ?

The solution to log_{10}(2)+log_{10}(3)+log_{10}(4) is log_{10}(24)

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simplify log_{10}(2)+log_{10}(3)+log_{10}(4)

simplify

lo g_{10} (2) + lo g_{10} (3) + lo g_{10} (4)

lo g_{10} (24)

Decimal Notation

1.38021 \dots

Solution steps

lo g_{10} (2) + lo g_{10} (3) + lo g_{10} (4)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (2) + lo g_{10} (3) = lo g_{10} (2 \cdot 3)

= lo g_{10} (2 \cdot 3) + lo g_{10} (4)

Multiply the numbers:

2 \cdot 3 = 6

= lo g_{10} (6) + lo g_{10} (4)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (6) + lo g_{10} (4) = lo g_{10} (6 \cdot 4)

= lo g_{10} (6 \cdot 4)

Multiply the numbers:

6 \cdot 4 = 24

= lo g_{10} (24)

\frac{2}{3} ln (x) - \frac{1}{2} ln (y)

ln (\frac{1}{x ^{n}})

lo g_{3} (6) - lo g_{3} (4)

lo g_{10} (\frac{6}{x})

lo g_{3} (7 x)

What is log_{10}(2)+log_{10}(3)+log_{10}(4) ?
The solution to log_{10}(2)+log_{10}(3)+log_{10}(4) is log_{10}(24)