What is log_{10}(6)-log_{10}(2)+log_{10}(d) ?

The solution to log_{10}(6)-log_{10}(2)+log_{10}(d) is log_{10}(3d)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}(6)-log_{10}(2)+log_{10}(d)

simplify

lo g_{10} (6) - lo g_{10} (2) + lo g_{10} (d)

lo g_{10} (3 d)

Solution steps

lo g_{10} (6) - lo g_{10} (2) + lo g_{10} (d)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (6) - lo g_{10} (2) = lo g_{10} (\frac{6}{2})

= lo g_{10} (\frac{6}{2}) + lo g_{10} (d)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (\frac{6}{2}) + lo g_{10} (d) = lo g_{10} (\frac{6}{2} d)

= lo g_{10} (\frac{6}{2} d)

Simplify

\frac{6}{2} d : 3 d

= lo g_{10} (3 d)

- lo g_{10} (6.3 \cdot 1 0^{- 5})

lo g_{10} (3 \cdot 2^{3})

\frac{1}{2} lo g_{c} (x) + 4 lo g_{c} (y) - 3 lo g_{c} (x)

ln (12 x)

What is log_{10}(6)-log_{10}(2)+log_{10}(d) ?
The solution to log_{10}(6)-log_{10}(2)+log_{10}(d) is log_{10}(3d)