What is log_{10}(4x+9)-log_{10}(x) ?

The solution to log_{10}(4x+9)-log_{10}(x) is log_{10}((4x+9)/x)

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simplify log_{10}(4x+9)-log_{10}(x)

simplify

lo g_{10} (4 x + 9) - lo g_{10} (x)

lo g_{10} (\frac{4 x + 9}{x})

Solution steps

lo g_{10} (4 x + 9) - lo g_{10} (x)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (4 x + 9) - lo g_{10} (x) = lo g_{10} (\frac{4 x + 9}{x})

= lo g_{10} (\frac{4 x + 9}{x})

5 ln (x) + 6 ln (y) - 2 ln (z)

lo g_{2} (k^{2} - 4) - lo g_{2} (k) - 2

2 lo g_{2} (x + 1) - lo g_{2} (x + 3) - lo g_{2} (x - 1)

\frac{1}{3} ln (2)

ln (a \cdot b)

What is log_{10}(4x+9)-log_{10}(x) ?
The solution to log_{10}(4x+9)-log_{10}(x) is log_{10}((4x+9)/x)