What are the solutions to the equation -x^2+20x=0 ?

The solutions to the equation -x^2+20x=0 are x=0,x=20

Find the zeros of -x^2+20x=0

The zeros of -x^2+20x=0 are x=0,x=20

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- x^{2} + 20 x = 0

x = 0, x = 20

Solution steps

- x^{2} + 20 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

2 0^{2} - 4 (- 1) \cdot 0 = 20

x_{1, 2} = \frac{- 20 \pm 20}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 20 + 20}{2 ( - 1 )}, x_{2} = \frac{- 20 - 20}{2 ( - 1 )}

x = \frac{- 20 + 20}{2 ( - 1 )} : 0

x = \frac{- 20 - 20}{2 ( - 1 )} : 20

The solutions to the quadratic equation are:

x = 0, x = 20

\frac{x ^{2} + 7 x - 8}{x ^{2} - 8 x + 16} \geq 0

lo g_{3} (2187) = x

x^{2} > - 1

15 x^{2} - 22 x + 8

y^{2} + 4 y + 29 = 0

What are the solutions to the equation -x^2+20x=0 ?
The solutions to the equation -x^2+20x=0 are x=0,x=20
Find the zeros of -x^2+20x=0
The zeros of -x^2+20x=0 are x=0,x=20