What is log_{10}(x)+log_{10}(24)-log_{10}(2) ?

The solution to log_{10}(x)+log_{10}(24)-log_{10}(2) is log_{10}(12x)

Popular >

simplify log_{10}(x)+log_{10}(24)-log_{10}(2)

simplify

lo g_{10} (x) + lo g_{10} (24) - lo g_{10} (2)

lo g_{10} (12 x)

Solution steps

lo g_{10} (x) + lo g_{10} (24) - lo g_{10} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (x) + lo g_{10} (24) = lo g_{10} (x \cdot 24)

= lo g_{10} (x \cdot 24) - lo g_{10} (2)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (x \cdot 24) - lo g_{10} (2) = lo g_{10} (\frac{x \cdot 24}{2})

= lo g_{10} (\frac{x \cdot 24}{2})

Simplify

\frac{x \cdot 24}{2} : x \cdot 12

= lo g_{10} (x \cdot 12)

= lo g_{10} (12 x)

lo g_{3} (10 z)

lo g_{10} (x yz)

ln (\frac{1}{2} x)

5 ln (x) - \frac{5}{3} ln (y) - 6 ln (w^{2}) + 9 ln (z)

lo g_{5} (3 x)

What is log_{10}(x)+log_{10}(24)-log_{10}(2) ?
The solution to log_{10}(x)+log_{10}(24)-log_{10}(2) is log_{10}(12x)