What is log_{5}(4)+log_{5}(4/125) ?

The solution to log_{5}(4)+log_{5}(4/125) is log_{5}(16/125)

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simplify log_{5}(4)+log_{5}(4/125)

simplify

lo g_{5} (4) + lo g_{5} (\frac{4}{125})

lo g_{5} (\frac{16}{125})

Decimal Notation

- 1.27729 \dots

Solution steps

lo g_{5} (4) + lo g_{5} (\frac{4}{125})

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{5} (4) + lo g_{5} (\frac{4}{125}) = lo g_{5} (4 \cdot \frac{4}{125})

= lo g_{5} (4 \cdot \frac{4}{125})

4 \cdot \frac{4}{125} = \frac{16}{125}

= lo g_{5} (\frac{16}{125})

ln (9 e)

ln (\frac{e x}{y}) - ln (\frac{y}{e x})

ln (z) - ln (x) - ln (y)

6 lo g_{10} (q) + lo g_{10} (x)

ln (\frac{0.8}{2})

What is log_{5}(4)+log_{5}(4/125) ?
The solution to log_{5}(4)+log_{5}(4/125) is log_{5}(16/125)