What are the solutions to the equation 2x^2-3x+17=0 ?

The solutions to the equation 2x^2-3x+17=0 are x= 3/4+i(sqrt(127))/4 ,x= 3/4-i(sqrt(127))/4

Find the zeros of 2x^2-3x+17=0

The zeros of 2x^2-3x+17=0 are x= 3/4+i(sqrt(127))/4 ,x= 3/4-i(sqrt(127))/4

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2 x^{2} - 3 x + 17 = 0

x = \frac{3}{4} + i \frac{127}{4}, x = \frac{3}{4} - i \frac{127}{4}

Solution steps

2 x^{2} - 3 x + 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 \cdot 17}{2 \cdot 2}

Simplify

(- 3)^{2} - 4 \cdot 2 \cdot 17 : 127 i

x_{1, 2} = \frac{- ( - 3 ) \pm 127 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 127 i}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 127 i}{2 \cdot 2}

x = \frac{- ( - 3 ) + 127 i}{2 \cdot 2} : \frac{3}{4} + i \frac{127}{4}

x = \frac{- ( - 3 ) - 127 i}{2 \cdot 2} : \frac{3}{4} - i \frac{127}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} + i \frac{127}{4}, x = \frac{3}{4} - i \frac{127}{4}

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What are the solutions to the equation 2x^2-3x+17=0 ?
The solutions to the equation 2x^2-3x+17=0 are x= 3/4+i(sqrt(127))/4 ,x= 3/4-i(sqrt(127))/4
Find the zeros of 2x^2-3x+17=0
The zeros of 2x^2-3x+17=0 are x= 3/4+i(sqrt(127))/4 ,x= 3/4-i(sqrt(127))/4