What is log_{10}((1+x)/(1-x)) ?

The solution to log_{10}((1+x)/(1-x)) is log_{10}(1+x)-log_{10}(1-x)

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simplify log_{10}((1+x)/(1-x))

simplify

lo g_{10} (\frac{1 + x}{1 - x})

lo g_{10} (1 + x) - lo g_{10} (1 - x)

Solution steps

lo g_{10} (\frac{1 + x}{1 - x})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{1 + x}{1 - x}) = lo g_{10} (1 + x) - lo g_{10} (1 - x)

= lo g_{10} (1 + x) - lo g_{10} (1 - x)

- \frac{1}{3} \cdot lo g_{2} (\frac{1}{3}) - \frac{2}{3} \cdot lo g_{2} (\frac{2}{3})

lo g_{10} (y^{2} - 3 y + 2) - lo g_{10} (y^{2} - 1)

ln (\frac{3859}{35109})

lo g_{2} (\frac{64}{250}) + 6 lo g_{4} (5)

lo g_{2} (x y)

What is log_{10}((1+x)/(1-x)) ?
The solution to log_{10}((1+x)/(1-x)) is log_{10}(1+x)-log_{10}(1-x)