What is log_{10}(12)-log_{10}(4) ?

The solution to log_{10}(12)-log_{10}(4) is log_{10}(3)

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simplify log_{10}(12)-log_{10}(4)

simplify

lo g_{10} (12) - lo g_{10} (4)

lo g_{10} (3)

Decimal Notation

0.47712 \dots

Solution steps

lo g_{10} (12) - lo g_{10} (4)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (12) - lo g_{10} (4) = lo g_{10} (\frac{12}{4})

= lo g_{10} (\frac{12}{4})

Divide the numbers:

\frac{12}{4} = 3

= lo g_{10} (3)

(\frac{1}{2} arctan (\frac{e ^{x}}{2})) - (\frac{1}{2} ln (4 + e^{2 x}))

lo g_{9} (\frac{f}{81})

lo g_{b} (\frac{x ^{6} - x ^{2} y ^{4}}{y ^{3} z w ^{2}})

lo g_{10} (\frac{3 x ^{4}}{t})

lo g_{2} (\frac{- 3 m ^{2} n ^{4}}{4 p})

What is log_{10}(12)-log_{10}(4) ?
The solution to log_{10}(12)-log_{10}(4) is log_{10}(3)