What is log_{10}(2x+7)-log_{10}(x) ?

The solution to log_{10}(2x+7)-log_{10}(x) is log_{10}((2x+7)/x)

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simplify log_{10}(2x+7)-log_{10}(x)

simplify

lo g_{10} (2 x + 7) - lo g_{10} (x)

lo g_{10} (\frac{2 x + 7}{x})

Solution steps

lo g_{10} (2 x + 7) - lo g_{10} (x)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (2 x + 7) - lo g_{10} (x) = lo g_{10} (\frac{2 x + 7}{x})

= lo g_{10} (\frac{2 x + 7}{x})

ln (x) + ln (x + 2)

lo g_{2} (7 x)

lo g_{b} (y^{7} z)

3 lo g_{b} (m + 2) + \frac{1}{2} lo g_{b} (m)

ln (7 e)

What is log_{10}(2x+7)-log_{10}(x) ?
The solution to log_{10}(2x+7)-log_{10}(x) is log_{10}((2x+7)/x)