What is log_{10}((m^2+n)/(100)) ?

The solution to log_{10}((m^2+n)/(100)) is log_{10}(m^2+n)-2

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simplify log_{10}((m^2+n)/(100))

simplify

lo g_{10} (\frac{m ^{2} + n}{100})

lo g_{10} (m^{2} + n) - 2

Solution steps

lo g_{10} (\frac{m ^{2} + n}{100})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{m ^{2} + n}{100}) = lo g_{10} (m^{2} + n) - lo g_{10} (100)

= lo g_{10} (m^{2} + n) - lo g_{10} (100)

lo g_{10} (100) = 2

= lo g_{10} (m^{2} + n) - 2

lo g_{2} (\frac{8}{y})

2 ln (\frac{53}{2}) + 12

lo g_{10} (\frac{a ^{2} \times b}{c})

lo g_{2} (\frac{1}{32} p^{3} q)

6 lo g_{2} (x) - 7 lo g_{2} (y)

What is log_{10}((m^2+n)/(100)) ?
The solution to log_{10}((m^2+n)/(100)) is log_{10}(m^2+n)-2