What is log_{10}(x+1)-log_{10}(x) ?

The solution to log_{10}(x+1)-log_{10}(x) is log_{10}((x+1)/x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}(x+1)-log_{10}(x)

simplify

lo g_{10} (x + 1) - lo g_{10} (x)

lo g_{10} (\frac{x + 1}{x})

Solution steps

lo g_{10} (x + 1) - lo g_{10} (x)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (x + 1) - lo g_{10} (x) = lo g_{10} (\frac{x + 1}{x})

= lo g_{10} (\frac{x + 1}{x})

ln (\frac{e}{5})

lo g_{3} (9 x)

lo g_{30} (64) + lo g_{30} (1 5^{3}) - 3 lo g_{30} (2)

2 lo g_{10} (x) + lo g_{10} (11)

What is log_{10}(x+1)-log_{10}(x) ?
The solution to log_{10}(x+1)-log_{10}(x) is log_{10}((x+1)/x)