What is 1/6 log_{2}(25)-1/3 log_{2}(10) ?

The solution to 1/6 log_{2}(25)-1/3 log_{2}(10) is -1/3

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simplify 1/6 log_{2}(25)-1/3 log_{2}(10)

simplify

\frac{1}{6} lo g_{2} (25) - \frac{1}{3} lo g_{2} (10)

- \frac{1}{3}

Decimal Notation

- 0.33333 \dots

Solution steps

\frac{1}{6} lo g_{2} (25) - \frac{1}{3} lo g_{2} (10)

\frac{1}{6} lo g_{2} (25) = \frac{1}{3} lo g_{2} (5)

\frac{1}{3} lo g_{2} (10) = \frac{1}{3} + \frac{1}{3} lo g_{2} (5)

= \frac{1}{3} lo g_{2} (5) - (\frac{1}{3} + \frac{1}{3} lo g_{2} (5))

Expand

- (\frac{1}{3} + \frac{1}{3} lo g_{2} (5)) : - \frac{1}{3} - \frac{1}{3} lo g_{2} (5)

= \frac{1}{3} lo g_{2} (5) - \frac{1}{3} - \frac{1}{3} lo g_{2} (5)

Add similar elements:

\frac{1}{3} lo g_{2} (5) - \frac{1}{3} lo g_{2} (5) = 0

= - \frac{1}{3}

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What is 1/6 log_{2}(25)-1/3 log_{2}(10) ?
The solution to 1/6 log_{2}(25)-1/3 log_{2}(10) is -1/3