What is log_{4}(2)+log_{4}(x)+log_{4}(y^2) ?

The solution to log_{4}(2)+log_{4}(x)+log_{4}(y^2) is log_{4}(2xy^2)

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simplify log_{4}(2)+log_{4}(x)+log_{4}(y^2)

simplify

lo g_{4} (2) + lo g_{4} (x) + lo g_{4} (y^{2})

lo g_{4} (2 x y^{2})

Solution steps

lo g_{4} (2) + lo g_{4} (x) + lo g_{4} (y^{2})

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{4} (2) + lo g_{4} (x) = lo g_{4} (2 x)

= lo g_{4} (2 x) + lo g_{4} (y^{2})

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{4} (2 x) + lo g_{4} (y^{2}) = lo g_{4} (2 x y^{2})

= lo g_{4} (2 x y^{2})

lo g_{4} (3) + lo g_{4} (8)

lo g_{2} (y^{x})

\frac{1}{2} lo g_{a} (x) + 4 lo g_{a} (y) - 3 lo g_{a} (x)

ln (x) + ln (17)

\frac{1}{2} ln (x) + 3 [ln (x - 1) - \frac{2}{9} ln (x + 1)]

What is log_{4}(2)+log_{4}(x)+log_{4}(y^2) ?
The solution to log_{4}(2)+log_{4}(x)+log_{4}(y^2) is log_{4}(2xy^2)