What is 2log_{10}(3x) ?

The solution to 2log_{10}(3x) is 2log_{10}(3)+2log_{10}(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 2log_{10}(3x)

simplify

2 lo g_{10} (3 x)

2 lo g_{10} (3) + 2 lo g_{10} (x)

Solution steps

2 lo g_{10} (3 x)

Apply log rule:

lo g_{a} (x y) = lo g_{a} (x) + lo g_{a} (y)

lo g_{10} (3 x) = lo g_{10} (3) + lo g_{10} (x)

= 2 (lo g_{10} (3) + lo g_{10} (x))

Apply the distributive law:

a (b + c) = ab + a c

2 (lo g_{10} (3) + lo g_{10} (x)) = 2 lo g_{10} (3) + 2 lo g_{10} (x)

= 2 lo g_{10} (3) + 2 lo g_{10} (x)

lo g_{10} (\frac{243}{32}) + lo g_{10} (\frac{32}{243})

lo g_{10} (\frac{1}{10 x})

ln (6) - ln (5)

4 lo g_{3} (x^{2}) - 3 lo g_{3} (x^{3})

lo g_{7} (\frac{2}{3})

What is 2log_{10}(3x) ?
The solution to 2log_{10}(3x) is 2log_{10}(3)+2log_{10}(x)