What are the solutions to the equation x(8x-7)=15 ?

The solutions to the equation x(8x-7)=15 are x= 15/8 ,x=-1

Find the zeros of x(8x-7)=15

The zeros of x(8x-7)=15 are x= 15/8 ,x=-1

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x (8 x - 7) = 15

x = \frac{15}{8}, x = - 1

Solution steps

x (8 x - 7) = 15

Expand

x (8 x - 7) : 8 x^{2} - 7 x

8 x^{2} - 7 x = 15

Move

15

to the left side

8 x^{2} - 7 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 8 ( - 15 )}{2 \cdot 8}

(- 7)^{2} - 4 \cdot 8 (- 15) = 23

x_{1, 2} = \frac{- ( - 7 ) \pm 23}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 23}{2 \cdot 8}, x_{2} = \frac{- ( - 7 ) - 23}{2 \cdot 8}

x = \frac{- ( - 7 ) + 23}{2 \cdot 8} : \frac{15}{8}

x = \frac{- ( - 7 ) - 23}{2 \cdot 8} : - 1

The solutions to the quadratic equation are:

x = \frac{15}{8}, x = - 1

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What are the solutions to the equation x(8x-7)=15 ?
The solutions to the equation x(8x-7)=15 are x= 15/8 ,x=-1
Find the zeros of x(8x-7)=15
The zeros of x(8x-7)=15 are x= 15/8 ,x=-1