What is log_{10}(x+1)+log_{10}(x-1) ?

The solution to log_{10}(x+1)+log_{10}(x-1) is log_{10}((x+1)(x-1))

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simplify log_{10}(x+1)+log_{10}(x-1)

simplify

lo g_{10} (x + 1) + lo g_{10} (x - 1)

lo g_{10} ((x + 1) (x - 1))

Solution steps

lo g_{10} (x + 1) + lo g_{10} (x - 1)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (x + 1) + lo g_{10} (x - 1) = lo g_{10} ((x + 1) (x - 1))

= lo g_{10} ((x + 1) (x - 1))

2 lo g_{10} (12) - 3 lo g_{10} (6) + 2 lo g_{10} (2)

lo g_{7} ((\frac{x ^{5}}{y})^{5})

ln (x ln (x))

lo g_{10} (7) - lo g_{10} (x)

lo g_{10} (2) + lo g_{10} (p)

What is log_{10}(x+1)+log_{10}(x-1) ?
The solution to log_{10}(x+1)+log_{10}(x-1) is log_{10}((x+1)(x-1))