What are the solutions to the equation (x+1)^2=1 ?

The solutions to the equation (x+1)^2=1 are x=0,x=-2

Find the zeros of (x+1)^2=1

The zeros of (x+1)^2=1 are x=0,x=-2

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(x + 1)^{2} = 1

x = 0, x = - 2

Solution steps

(x + 1)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 1 : x = 0

Solve

x + 1 = - 1 : x = - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

x^{3} - 3 x + 2

3 x^{2} + 12 x + 6 = 0

a^{3} + 125

\frac{3 x - 3}{5} + \frac{x + 3}{3} = 6

3 (x - 3) = - 15

What are the solutions to the equation (x+1)^2=1 ?
The solutions to the equation (x+1)^2=1 are x=0,x=-2
Find the zeros of (x+1)^2=1
The zeros of (x+1)^2=1 are x=0,x=-2