What is log_{10}(x+2)+log_{10}(x-1) ?

The solution to log_{10}(x+2)+log_{10}(x-1) is log_{10}((x+2)(x-1))

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simplify log_{10}(x+2)+log_{10}(x-1)

simplify

lo g_{10} (x + 2) + lo g_{10} (x - 1)

lo g_{10} ((x + 2) (x - 1))

Solution steps

lo g_{10} (x + 2) + lo g_{10} (x - 1)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (x + 2) + lo g_{10} (x - 1) = lo g_{10} ((x + 2) (x - 1))

= lo g_{10} ((x + 2) (x - 1))

lo g_{b} (\frac{7}{6})

ln (\frac{x ^{2} x ^{2} - 1}{e ^{x}})

\frac{1}{3} lo g_{b} (x) + 4 lo g_{b} (y) - 2 lo g_{b} (x)

2 lo g_{10} (2) + 3 lo g_{10} (3) - 2 lo g_{10} (6)

lo g_{10} (\frac{a ^{5} a ^{2} b}{( ab ) ^{2}})

What is log_{10}(x+2)+log_{10}(x-1) ?
The solution to log_{10}(x+2)+log_{10}(x-1) is log_{10}((x+2)(x-1))