What is 10log_{10}(I/(I_{0)}) ?

The solution to 10log_{10}(I/(I_{0)}) is 10(log_{10}(I)-log_{10}(I))

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simplify 10log_{10}(I/(I_{0)})

simplify

10 lo g_{10} (\frac{I}{I _{0}})

10 (lo g_{10} (I) - lo g_{10} (I))

Solution steps

10 lo g_{10} (\frac{I}{I _{0}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{10} (\frac{I}{I _{0}}) = lo g_{10} (I) - lo g_{10} (I_{0})

= 10 (lo g_{10} (I) - lo g_{10} (I_{0}))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (I_{0}) = lo g_{10} (I)

= 10 (lo g_{10} (I) - lo g_{10} (I))

ln (\frac{r}{3 s})

ln (2) \frac{1}{3}

ln (\frac{21}{5})

lo g_{5} (5 x^{2})

lo g_{6} (x) - lo g_{6} (x^{7})

What is 10log_{10}(I/(I_{0)}) ?
The solution to 10log_{10}(I/(I_{0)}) is 10(log_{10}(I)-log_{10}(I))