What is simplify-6/8 log_{2}(6/8)-2/8 log_{2}(2/8) ?

The solution to simplify-6/8 log_{2}(6/8)-2/8 log_{2}(2/8) is -3/4 log_{2}(3/4)+1/2

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simplify-6/8 log_{2}(6/8)-2/8 log_{2}(2/8)

simplify

- \frac{6}{8} lo g_{2} (\frac{6}{8}) - \frac{2}{8} lo g_{2} (\frac{2}{8})

- \frac{3}{4} lo g_{2} (\frac{3}{4}) + \frac{1}{2}

Decimal Notation

0.81127 \dots

Solution steps

- \frac{6}{8} lo g_{2} (\frac{6}{8}) - \frac{2}{8} lo g_{2} (\frac{2}{8})

- \frac{6}{8} lo g_{2} (\frac{6}{8}) = - \frac{3}{4} lo g_{2} (\frac{3}{4})

\frac{2}{8} lo g_{2} (\frac{2}{8}) = - \frac{1}{2}

= - \frac{3}{4} lo g_{2} (\frac{3}{4}) - (- \frac{1}{2})

Apply rule:

a - (- b) = a + b

- \frac{3}{4} lo g_{2} (\frac{3}{4}) - (- \frac{1}{2}) = - \frac{3}{4} lo g_{2} (\frac{3}{4}) + \frac{1}{2}

= - \frac{3}{4} lo g_{2} (\frac{3}{4}) + \frac{1}{2}

- lo g_{b} (\frac{1}{5})

lo g_{10} (3) 3

- lo g_{10} (4.4 \cdot 1 0^{- 4})

lo g_{10} (8 k)

What is simplify-6/8 log_{2}(6/8)-2/8 log_{2}(2/8) ?
The solution to simplify-6/8 log_{2}(6/8)-2/8 log_{2}(2/8) is -3/4 log_{2}(3/4)+1/2