What is log_{10}(x/(x+1)) ?

The solution to log_{10}(x/(x+1)) is log_{10}(x)-log_{10}(x+1)

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simplify log_{10}(x/(x+1))

simplify

lo g_{10} (\frac{x}{x + 1})

lo g_{10} (x) - lo g_{10} (x + 1)

Solution steps

lo g_{10} (\frac{x}{x + 1})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{x}{x + 1}) = lo g_{10} (x) - lo g_{10} (x + 1)

= lo g_{10} (x) - lo g_{10} (x + 1)

3 lo g_{10} (a) - lo g_{10} (q)

ln (x^{2} - 9) + 2 ln (\frac{1}{x + 3}) + 4 ln (x)

lo g_{10} (w^{6} u \cdot v)

2 ln (a) - ln (b)

What is log_{10}(x/(x+1)) ?
The solution to log_{10}(x/(x+1)) is log_{10}(x)-log_{10}(x+1)