What is log_{b}(10)+log_{b}(7) ?

The solution to log_{b}(10)+log_{b}(7) is log_{b}(70)

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simplify log_{b}(10)+log_{b}(7)

simplify

lo g_{b} (10) + lo g_{b} (7)

lo g_{b} (70)

Solution steps

lo g_{b} (10) + lo g_{b} (7)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{b} (10) + lo g_{b} (7) = lo g_{b} (10 \cdot 7)

= lo g_{b} (10 \cdot 7)

Multiply the numbers:

10 \cdot 7 = 70

= lo g_{b} (70)

lo g_{2} (\frac{e ^{2}}{4})

ln (2 x + 1) + ln (x - 1) - 2 ln (x)

lo g_{2} (x^{2}) - 3 lo g_{2} (x + 1) + lo g_{4} (3 x)

ln (1 + x) - ln (1 - x)

\frac{3}{4} lo g_{2} (\frac{3}{4}) + \frac{1}{4} lo g_{2} (\frac{1}{4})

What is log_{b}(10)+log_{b}(7) ?
The solution to log_{b}(10)+log_{b}(7) is log_{b}(70)