What is log_{b}(1/10)+log_{b}(20) ?

The solution to log_{b}(1/10)+log_{b}(20) is log_{b}(2)

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simplify log_{b}(1/10)+log_{b}(20)

simplify

lo g_{b} (\frac{1}{10}) + lo g_{b} (20)

lo g_{b} (2)

Solution steps

lo g_{b} (\frac{1}{10}) + lo g_{b} (20)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{b} (\frac{1}{10}) + lo g_{b} (20) = lo g_{b} (\frac{1}{10} \cdot 20)

= lo g_{b} (\frac{1}{10} \cdot 20)

\frac{1}{10} \cdot 20 = 2

= lo g_{b} (2)

3 lo g_{10} (x) + 3 lo g_{10} (y)

lo g_{4} (\frac{8 y}{z})

lo g_{10} (\frac{1}{2}) + lo g_{10} (4) - 2

ln (\frac{8}{9 x ^{9} y})

lo g_{b} (6) + lo g_{b} (4)

What is log_{b}(1/10)+log_{b}(20) ?
The solution to log_{b}(1/10)+log_{b}(20) is log_{b}(2)