What is log_{10}(k^2-100)-log_{10}(k)-10 ?

The solution to log_{10}(k^2-100)-log_{10}(k)-10 is log_{10}((k^2-100)/k)-10

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simplify log_{10}(k^2-100)-log_{10}(k)-10

simplify

lo g_{10} (k^{2} - 100) - lo g_{10} (k) - 10

lo g_{10} (\frac{k ^{2} - 100}{k}) - 10

Solution steps

lo g_{10} (k^{2} - 100) - lo g_{10} (k) - 10

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (k^{2} - 100) - lo g_{10} (k) = lo g_{10} (\frac{k ^{2} - 100}{k})

= lo g_{10} (\frac{k ^{2} - 100}{k}) - 10

ln (\frac{3 d}{4 ^{- 1}})

\frac{1}{3} - 3 ln (\frac{1}{3})

lo g_{10} (5 \cdot 3)

ln (\frac{1}{25 k})

3 lo g_{a} (b) - \frac{1}{2} lo g_{a} (c)

What is log_{10}(k^2-100)-log_{10}(k)-10 ?
The solution to log_{10}(k^2-100)-log_{10}(k)-10 is log_{10}((k^2-100)/k)-10