What is expand log_{12}((12)/y) ?

The solution to expand log_{12}((12)/y) is 1-log_{12}(y)

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expand log_{12}((12)/y)

expand

lo g_{12} (\frac{12}{y})

1 - lo g_{12} (y)

Solution steps

lo g_{12} (\frac{12}{y})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{12} (\frac{12}{y}) = lo g_{12} (12) - lo g_{12} (y)

= lo g_{12} (12) - lo g_{12} (y)

Apply log rule:

lo g_{a} (a) = 1

= 1 - lo g_{12} (y)

- (\frac{5}{8}) lo g_{2} (\frac{5}{8}) - (\frac{3}{8}) lo g_{2} (\frac{3}{8})

5 ln (x) + 3 ln (y) - 4 ln (z)

lo g_{10} (6) + lo g_{10} (5) - lo g_{10} (15)

lo g_{10} (\frac{a ^{2}}{b ^{- 3} c ^{4}})

What is expand log_{12}((12)/y) ?
The solution to expand log_{12}((12)/y) is 1-log_{12}(y)