What is log_{2}(6)+log_{2}(3) ?

The solution to log_{2}(6)+log_{2}(3) is log_{2}(18)

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simplify log_{2}(6)+log_{2}(3)

simplify

lo g_{2} (6) + lo g_{2} (3)

lo g_{2} (18)

Decimal Notation

4.16992 \dots

Solution steps

lo g_{2} (6) + lo g_{2} (3)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (6) + lo g_{2} (3) = lo g_{2} (6 \cdot 3)

= lo g_{2} (6 \cdot 3)

Multiply the numbers:

6 \cdot 3 = 18

= lo g_{2} (18)

lo g_{3} (\frac{c}{27})

lo g_{10} (3) + 2 lo g_{10} (x)

lo g_{\frac{1}{2}} (\frac{3 x ^{2}}{2})

3 lo g_{10} (x) + 2 lo g_{10} (y) - 5 lo g_{10} (z)

2 ln (3) - ln (2)

What is log_{2}(6)+log_{2}(3) ?
The solution to log_{2}(6)+log_{2}(3) is log_{2}(18)