What is 2log_{10}(3x)-log_{10}(7x) ?

The solution to 2log_{10}(3x)-log_{10}(7x) is log_{10}((9x)/7)

Popular >

simplify 2log_{10}(3x)-log_{10}(7x)

simplify

2 lo g_{10} (3 x) - lo g_{10} (7 x)

lo g_{10} (\frac{9 x}{7})

Solution steps

2 lo g_{10} (3 x) - lo g_{10} (7 x)

Apply log rule:

b \cdot lo g_{a} (x) = lo g_{a} (x^{b})

2 lo g_{10} (3 x) = lo g_{10} ((3 x)^{2})

= lo g_{10} ((3 x)^{2}) - lo g_{10} (7 x)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} ((3 x)^{2}) - lo g_{10} (7 x) = lo g_{10} (\frac{( 3 x ) ^{2}}{7 x})

= lo g_{10} (\frac{( 3 x ) ^{2}}{7 x})

Simplify

\frac{( 3 x ) ^{2}}{7 x} : \frac{9 x}{7}

= lo g_{10} (\frac{9 x}{7})

5 ln (x) + 3 ln (y) - 2 ln (z)

lo g_{10} (\frac{y ^{4}}{x ^{5} z})

\frac{1}{4} lo g_{10} (33) + \frac{1}{4} lo g_{10} (44)

lo g_{b} (8 k)

lo g_{10} (1000 x)

What is 2log_{10}(3x)-log_{10}(7x) ?
The solution to 2log_{10}(3x)-log_{10}(7x) is log_{10}((9x)/7)