What are the solutions to the equation 2x^2+x+8=0 ?

The solutions to the equation 2x^2+x+8=0 are x=-1/4+i(3sqrt(7))/4 ,x=-1/4-i(3sqrt(7))/4

Find the zeros of 2x^2+x+8=0

The zeros of 2x^2+x+8=0 are x=-1/4+i(3sqrt(7))/4 ,x=-1/4-i(3sqrt(7))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + x + 8 = 0

x = - \frac{1}{4} + i \frac{3 7}{4}, x = - \frac{1}{4} - i \frac{3 7}{4}

Solution steps

2 x^{2} + x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

Simplify

1^{2} - 4 \cdot 2 \cdot 8 : 37 i

x_{1, 2} = \frac{- 1 \pm 3 7 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 3 7 i}{2 \cdot 2}, x_{2} = \frac{- 1 - 3 7 i}{2 \cdot 2}

x = \frac{- 1 + 3 7 i}{2 \cdot 2} : - \frac{1}{4} + i \frac{3 7}{4}

x = \frac{- 1 - 3 7 i}{2 \cdot 2} : - \frac{1}{4} - i \frac{3 7}{4}

The solutions to the quadratic equation are:

x = - \frac{1}{4} + i \frac{3 7}{4}, x = - \frac{1}{4} - i \frac{3 7}{4}

(x + 1) (x - 10) = 0

8 - \frac{3 x}{10} + \frac{2 x}{4} - \frac{5 x}{8} = - 9

4 x - \frac{2}{5} > \frac{3}{5}

19 - 2 (1 - x) < 13

3 x^{2} - 7 x + 9 = 0

What are the solutions to the equation 2x^2+x+8=0 ?
The solutions to the equation 2x^2+x+8=0 are x=-1/4+i(3sqrt(7))/4 ,x=-1/4-i(3sqrt(7))/4
Find the zeros of 2x^2+x+8=0
The zeros of 2x^2+x+8=0 are x=-1/4+i(3sqrt(7))/4 ,x=-1/4-i(3sqrt(7))/4