What is log_{10}(3)+log_{10}(4)-log_{10}(2) ?

The solution to log_{10}(3)+log_{10}(4)-log_{10}(2) is log_{10}(6)

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simplify log_{10}(3)+log_{10}(4)-log_{10}(2)

simplify

lo g_{10} (3) + lo g_{10} (4) - lo g_{10} (2)

lo g_{10} (6)

Decimal Notation

0.77815 \dots

Solution steps

lo g_{10} (3) + lo g_{10} (4) - lo g_{10} (2)

lo g_{10} (4) = 2 lo g_{10} (2)

= lo g_{10} (3) + 2 lo g_{10} (2) - lo g_{10} (2)

Add similar elements:

2 lo g_{10} (2) - lo g_{10} (2) = lo g_{10} (2)

= lo g_{10} (3) + lo g_{10} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (3) + lo g_{10} (2) = lo g_{10} (3 \cdot 2)

= lo g_{10} (3 \cdot 2)

Multiply the numbers:

3 \cdot 2 = 6

= lo g_{10} (6)

lo g_{a} (\frac{x ^{3} w}{y ^{2} z ^{4}})

- lo g_{10} (1.4 \cdot 1 0^{- 5})

\frac{1}{2} lo g_{10} (x) + 5 lo g_{10} (y)

(lo g_{b} (x) - lo g_{b} (y)) + 7 lo g_{b} (v)

4 ln (x) + 3 ln (y) - 2 ln (z)

What is log_{10}(3)+log_{10}(4)-log_{10}(2) ?
The solution to log_{10}(3)+log_{10}(4)-log_{10}(2) is log_{10}(6)