What is log_{4}(x+1)+log_{4}(4x-3) ?

The solution to log_{4}(x+1)+log_{4}(4x-3) is log_{4}((x+1)(4x-3))

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simplify log_{4}(x+1)+log_{4}(4x-3)

simplify

lo g_{4} (x + 1) + lo g_{4} (4 x - 3)

lo g_{4} ((x + 1) (4 x - 3))

Solution steps

lo g_{4} (x + 1) + lo g_{4} (4 x - 3)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{4} (x + 1) + lo g_{4} (4 x - 3) = lo g_{4} ((x + 1) (4 x - 3))

= lo g_{4} ((x + 1) (4 x - 3))

lo g_{10} (10 x^{100}) 5

2 ln (x) - \frac{1}{7} ln (y)

lo g_{b} (\frac{1}{10}) + lo g_{b} (50)

lo g_{2} (5) + lo g_{2} (x)

lo g_{10} (z^{3} x^{5} y)

What is log_{4}(x+1)+log_{4}(4x-3) ?
The solution to log_{4}(x+1)+log_{4}(4x-3) is log_{4}((x+1)(4x-3))