What is 1/2 (log_{7}(r-2)-log_{7}(r)) ?

The solution to 1/2 (log_{7}(r-2)-log_{7}(r)) is (log_{7}((r-2)/r))/(2)

Popular >

simplify 1/2 (log_{7}(r-2)-log_{7}(r))

simplify

\frac{1}{2} (lo g_{7} (r - 2) - lo g_{7} (r))

\frac{lo g _{7} ( \frac{r - 2}{r} )}{2}

Solution steps

\frac{1}{2} (lo g_{7} (r - 2) - lo g_{7} (r))

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{7} (r - 2) - lo g_{7} (r) = lo g_{7} (\frac{r - 2}{r})

= \frac{1}{2} lo g_{7} (\frac{r - 2}{r})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot lo g _{7} ( \frac{r - 2}{r} )}{2}

Apply rule:

1 \cdot a = a

1 \cdot lo g_{7} (\frac{r - 2}{r}) = lo g_{7} (\frac{r - 2}{r})

= \frac{lo g _{7} ( \frac{r - 2}{r} )}{2}

lo g_{b} (x^{2}) y

lo g_{4} (5) + lo g_{4} (9)

10 lo g_{10} (5 x)

lo g_{4} (\frac{3 x - 5}{x})

lo g_{10} (\frac{2 a ^{5}}{27})

What is 1/2 (log_{7}(r-2)-log_{7}(r)) ?
The solution to 1/2 (log_{7}(r-2)-log_{7}(r)) is (log_{7}((r-2)/r))/(2)